Eric,
In the XPath data model, each node has a "Base URI" associated with it,
which you could use for this purpose if you could only get access to it.
Unfortunately there's no function in XPath 1.0 that will give it to you.
There may be hacks or tricks you could use, or honest extension functions,
to get this value, depending on your processor. But the easiest and most
portable way to get the value into your stylesheet is simply to pass the
file name in as a string parameter, at runtime.
Ask again if you can't figure out how to do this.
Oh, and, strictly speaking you're not allowed to use "xml" as an element
name (though not all processors enforce this restriction).
Cheers,
Wendell
At 12:48 PM 2/19/2004, you wrote:
I seem to have a catch-22 here that my mind can't get around, as I try to
convert from hard-coded html to XSL. I've got an XML file with a ref to
an XSL, eg.
<?xml-stylesheet type="text/xsl" href="Test.xsl"?>
<xml> ... </xml>
The stylesheet has all the usual stuff, but also this attribute:
<xml id="Info" src="h:\temp\dccase.xml" />
My problem is that I *want* the src to be is the very XML document that
called the XSL in the first place. How would I do that?
======================================================================
Wendell Piez
mailto:wapiez(_at_)mulberrytech(_dot_)com
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
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