RE: 2 Predicates in 1 for-each, possible?

A predicate is used to filter a selection by converting the contents to a 
boolean value. 

Your selection is //communication/email, which translates to 
/descendant-or-self::node()/communication/email.
Alone this will return all email elements with a communication element as 
parent. 

Adding the predicate [emailaddress] specifies that you only want email nodes 
with an emailaddress node as a child. emailaddress will evaluate to true if 
there is an emailaddress child element of the selected node.

the predicate [//communication2[emailaddress2]] evaluates to true when there 
exists a communication2 element with a child emailaddress2 element anywhere in 
the document.

the predicate [emailaddress or //communication2[emailaddress2]] returns true 
when either of the two conditions described above are true.

It looks like you really want the union of all communication/email and 
communication2/emailaddress2 nodes.

<xsl:for-each select="//communication/email[emailaddress] | 
//communication2/emailaddress2">

Good luck,
Josh

-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]On Behalf Of Bert
Sent: Tuesday, February 10, 2004 12:29 PM
To: Xsl-List
Subject: [xsl] 2 Predicates in 1 for-each, possible?


Hello,

Allow me to ask a question about 2 predicates in 1 for-each.

I have this xml-file:

<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="persons01.xsl"?>

<root>
 <organisation>
  <communication>
   <email>
    <emailaddress>e-mail(_at_)bert(_dot_)nl(1)</emailaddress>
   </email>
  </communication>
  <communication2>
   <emailaddress2>e-mail(_at_)bert(_dot_)nl(2)</emailaddress2>
  </communication2>
 </organisation>
 <organisation>
  <communication>
   <email>
    <emailaddress>e-mail(_at_)you(_dot_)nl(1)</emailaddress>
   </email>
  </communication>
  <communication2>
   <emailaddress2>e-mail(_at_)you(_dot_)nl(2)</emailaddress2>
  </communication2>
 </organisation>
</root>

I use this stylesheet to collect some information:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 <xsl:output method="xml" indent="yes"/>
 <xsl:template match="/">
  <document>
   <xsl:for-each select="//communication/email[emailaddress or
//communication2[emailaddress2]]">
    <xsl:sort select="."/>
    <xsl:value-of select="."/>
    <xsl:if test="position() != last()">,
    </xsl:if>
   </xsl:for-each>
  </document>
 </xsl:template>
</xsl:stylesheet>

I expected to get the following result:
e-mail(_at_)bert(_dot_)nl(1), e-mail(_at_)bert(_dot_)nl(2), 
e-mail(_at_)you(_dot_)nl(1), e-mail(_at_)you(_dot_)nl(2)

But what I get is this:
e-mail(_at_)bert(_dot_)nl(1) , e-mail(_at_)you(_dot_)nl(1)

It is obvious there is something wrong in my for-each-statement, but what?

Any help is this is welcome.

Kind regards,
Bert



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