Thank you David
This is my expected result.
I thought assign node from second XML so, I need to
access with common attribute to fetch uniquly.
This is works fine.
Regards
Arul
--- David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk> wrote:
<xsl:apply-templates
select="$dataxmltmp//field[(_at_)name=$nametmp]/assign">
OK so at this point you have moved the current node
over to the other
file and will process the two assign elements which
are children of
<field name="table4">
You are passing a parameter but I don't think you
need that.
But in your template for assign
why do this:
<xsl:value-of
select="$dataxmltmp//field[(_at_)name=$nametmp]/assign/
$dataxmltmp//field[(_at_)name=$nametmp]/assign/
It ignores the assign element you are on and always
selects the
same (two) assign elements. The as you use value-of
it always uses
the first of these, so you get the result you
stated.
I think that you just want
<xsl:template match="assign">
<xsl:value-of select="@name"/>
<xsl:text>=</xsl:text>
<xsl:value-of select="@value"/><xsl:text>;
</xsl:text>
</xsl:template>
--
http://www.dcarlisle.demon.co.uk/matthew
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