<xsl:template match="/">
<xsl:value-of select="//CutAddress[AddressType = 'Service']"/>
</xsl:template>
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Kotes Mogili
Sent: Tuesday, February 03, 2004 3:04 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Need expression..
Hi,
I want to go to a node directly through XPath expression. For example I
need to select AddressLine1 from CutAddress where AddressType='Service'.
Currently I am using
.//*[AddressType='Service']/AddressLine1. But when I use
.//CutAddress[AddressType='Service']/AddressLine1 it is not working.Can
anybody correct me??
Thanks
Kotes
<SiebelMessage MessageId="" MessageType="Integration Object"
IntObjectName="Txn 28 IO">
<VitriaDescriptionOut028>
<Account>
<ListOfAccountSalesInfo>
<AccountSalesInfo>
<LDLocal>Local</LDLocal>
<SalesAgentCode/>
<SalesContact/>
<SalesSourceCode/>
</AccountSalesInfo>
<AccountSalesInfo>
<LDLocal>LD</LDLocal>
<SalesAgentCode/>
<SalesContact/>
<SalesSourceCode/>
</AccountSalesInfo>
</ListOfAccountSalesInfo>
<ListOfCutAddress>
<CutAddress>
<AddressLine1>365 HUNTSMILL BLVD</AddressLine1>
<AddressLine2/>
<AddressName/>
<AddressType>Service</AddressType>
<City>SCARBOROUGH</City>
<PostalCode>M1W2Y9</PostalCode>
<State>ON</State>
</CutAddress>
<CutAddress>
<AddressLine1>366 HUNSTMILL BLVD</AddressLine1>
<AddressLine2/>
<AddressName/>
<AddressType>Billing</AddressType>
<City>SCARBOROUGH</City>
<PostalCode>M1W2Y9</PostalCode>
<State>ON</State>
</CutAddress>
<CutAddress>
<AddressLine1>364 HUNTSMILL BLVD</AddressLine1>
<AddressLine2/>
<AddressName/>
<AddressType>Main</AddressType>
<City>SCARBOROUGH</City>
<PostalCode>M1W2Y9</PostalCode>
<State>ON</State>
</CutAddress>
</ListOfCutAddress>
</Account>
</VitriaDescriptionOut028>
</SiebelMessage>
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