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Re: Problem setting variable in if statement

2004-02-02 12:59:27
At 2004-02-02 12:02 -0700, Johnson, Kaerstin wrote:
I am very new to xsl/xslt and have a basic problem.  I am setting a style
sheet color based on a condition.
I'd like the color to be a variable value, like
<xsl:variable name="statColor" select="#33cc33">
and set this variable in the if/choose condtion.

In XSLT you have to turn this inside out:

<xsl:variable name="statColor">
  <xsl:choose>
    <xsl:when test="status='inprogress'">#33cc33</xsl:when>
    <xsl:when>...
  </xsl:choose>
</xsl:variable>

Then it is in scope for all following siblings and their descendants, and you can go ahead and use it as desired:

Then recall it like
<span style="color:{$statColor}"><xsl:value-of select="status"></span>

I hope this helps.

........................ Ken


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