do you want to open the link with a parameter which type of pers_data you want
to show or is this all on one file?
in case of the parameter you need to provide information which environment you
work in (servlet?)
if you want to put it all in one file you could do something like:
<xsl:template match="/">
<!-- this is slow, better to select the proper nesting if possible -->
<xsl:apply-templates select="//pers-data"/>
</xsl:template>
<xsl:template match="pers_data">
<p>
<!-- @ is the same as attribute:: but i think much neater cause
it is shorter -->
<a href="test.xml?param={parent::node/@type}">
<xsl:value-of select="parent::node/@type"/>
</a>
</p>
</xsl:template>
is that what you were trying to do?
chris
-----Ursprüngliche Nachricht-----
Von: Markus Hanel [mailto:markus(_dot_)hanel(_at_)gmx(_dot_)at]
Gesendet: Dienstag, 30. März 2004 10:21
An: xsl mailinglist
Betreff: [xsl] change a attribute with a link?
hello,
I want to list some informations of pers_datas of some nodes.
The routine is
equal for the attribut "admin", "interviewees" and
"interviewer" of this
nodes. My idear is to make 3 links, every link opens the same
file and evaluates
with one of the attributes: admin, interviewees or
interviewer. Therefore I
had to change the value of "attribute::type" of the xslt elements:
apply-templates and template. Is there a possibility to arange this?
xml file
<node type="admin">
<pers_data></pers_data>
<node type="school">
<node type="interviewees">
<pers_data></pers_data>
<pers_data></pers_data>
<pers_data></pers_data>
</node>
<node type="department">
<node type="interviewer">
<pers_data></pers_data>
<pers_data></pers_data>
<pers_data></pers_data>
</node>
...
xsl file
<xsl:stylesheet>
...
<p><a><xsl:attribute name="href">test.xml</xsl:attribute>evaluate the
admin</a></p>
<p><a><xsl:attribute name="href">test.xml</xsl:attribute>evaluate the
interviewees</a></p>
<p><a><xsl:attribute name="href">test.xml</xsl:attribute>evaluate the
interviewer</a></p>
...
<xsl:apply-templates
select="descendant-or-self::node[attribute::type =
'admin']" />
....................................should change to
[attribute::type =
'interviewees']
<xsl:template match="node[attribute::type = 'admin']">
...
</xsl:template>
</xsl:stylesheet>
Many thanks
markus
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