Your path is incomplete.
<xsl:template match="/">
<xsl:for-each select="struct/member/value[string='Syndicated']">
Your template match is putting your context at the root of the document so your
for-each is looking for a "struct" node relative to the root, but there isn't
one.
You can fully specify the path like this:
<xsl:for-each
select="methodResponse/params/param/value/array/data/value/struct/member/value[string='Syndicated']">
This explicitly tells the xpath processor where to find the nodes.
Josh
-----Original Message-----
From: Dylan Barber [mailto:dylan(_dot_)barber(_at_)earthlink(_dot_)net]
Sent: Thursday, March 25, 2004 9:33 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Some help with xsl transform and filter please
Okay hope I am not asking something so basic everyone thinks I am a dunce but i
have an xml document that comes from a web service like this
<?xml version="1.0" encoding="iso-8859-1" ?>
<methodResponse>
<params>
<param>
<value>
<array>
<data>
<value>
<struct>
<member>
<name>feedid</name>
<value>
<string>2403</string>
</value>
</member>
<member>
<name>status</name>
<value>
<string>Syndicated</string>
</value>
</member>
</struct>
</value>
</data>
</array>
</value>
</param>
</params>
</methodResponse>
I have tried to transform it with something like this
<xsl:template match="/">
<xsl:for-each select="struct/member/value[string='Syndicated']">
<xsl:value-of select="name" />
:
<xsl:value-of select="string" />
;<br />
</xsl:for-each>
</xsl:for-each>
</xsl:template>
but this doesnt seem to work. I am a newbie with this whole thing and really
need some guidance on how this whole xsl xml thing goes together. Sorry if I
have missed the obvious or broken any rules.
Dylan Barber (CIW Professional, A+ Technician, Web Designer, Web Developer)
home phone-:- (785) 765-2664
work phone-:- (785) 539-3565 x1034
email-:- dylan(_dot_)barber(_at_)earthlink(_dot_)net
homesite-:- http://www.codegalaxy.com
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