RE: How to use xpath in this xml file...

Sorry, earlier xslt was incorrect.  Try this with the xml I provided(it
helps to have different ANNO values):

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="PENSIONES">
        <xsl:for-each select="DETALLE_PENSION/ANNO">
                
                <xsl:value-of select="."/> = = <xsl:value-of
select="preceding::ANNO[1]"/> :: <xsl:value-of select=". =
preceding::ANNO[1]"/>
                <br/>
                
        </xsl:for-each>
</xsl:template>
</xsl:stylesheet>

Basically, loop through all DETALLE_PENSION/ANNO and get the value of the
ANNO (".")

Then compare preceding::ANNO[1](the very prior ANNO node).  For some reason
this will not work without the [1], although it was my impression that the
[1] was implicitly implied.  


Here is the output:

1998 = = :: false
1998 = = 1998 :: true
1998 = = 1998 :: true
1999 = = 1998 :: false
1998 = = 1999 :: false
1998 = = 1998 :: true

-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of 
BECAPORTAL2
becario desarrollo
Sent: Wednesday, March 17, 2004 8:47 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] How to use xpath in this xml file...

Hi everybody,

I have a xml file like this:

<PENSIONES>
        <NOMBRE>28509599H</NOMBRE>
        <numCol>1</numCol>
        <Volver>0</Volver>
        <CIF>P4100000A</CIF>
        <RAZONSOCIAL>DIPUTACION PROVINCIAL DE SEVILLA</RAZONSOCIAL>
        <TOTAL_APORT_EMP>4.640,55</TOTAL_APORT_EMP>
        <TOTAL_APORT_TRAB>1.969,44</TOTAL_APORT_TRAB>
        <accion>listadoPensiones</accion>
        <desde>1</desde>
        <DETALLE_PENSION>
                <ANNO>1998</ANNO>
                <MES>4</MES>
                <APORT_EMP>1.514,55</APORT_EMP>
                <APORT_TRAB>0</APORT_TRAB>
        </DETALLE_PENSION>
        <DETALLE_PENSION>
                <ANNO>1998</ANNO>
                <MES>5</MES>
                <APORT_EMP>42,07</APORT_EMP>
                <APORT_TRAB>8,41</APORT_TRAB>
        </DETALLE_PENSION>
        <DETALLE_PENSION>
                <ANNO>1998</ANNO>
                <MES>6</MES>
                <APORT_EMP>42,07</APORT_EMP>
                <APORT_TRAB>8,41</APORT_TRAB>
        </DETALLE_PENSION>
        <DETALLE_PENSION>
                <ANNO>1998</ANNO>
                <MES>7</MES>
                <APORT_EMP>42,07</APORT_EMP>
                <APORT_TRAB>8,41</APORT_TRAB>
        </DETALLE_PENSION>
        <DETALLE_PENSION>
                <ANNO>1998</ANNO>
                <MES>8</MES>
                <APORT_EMP>42,07</APORT_EMP>
                <APORT_TRAB>8,41</APORT_TRAB>
        </DETALLE_PENSION>
        <DETALLE_PENSION>
                <ANNO>1998</ANNO>
                <MES>9</MES>
                <APORT_EMP>42,07</APORT_EMP>
                <APORT_TRAB>8,41</APORT_TRAB>
        </DETALLE_PENSION>
        <hasta>70</hasta>
        <registros>71</registros>
</PENSIONES>

 When i select value of "ANNO" with xsl, i would like compare with last
value of ANNO. I have trying with precedence,ancestor,position(), but i have
failled. Which xpath sentence will be good in this case?

Thanks in advance and Greetings from Spain


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