xmlns "attributes" are represented as namespace nodes in the data model, not
as attribute nodes. You can find them using the namespace axis
(namespace::*). Note that this finds all the namespaces in scope, including
those declared on ancestor elements.
Michael Kay
# -----Original Message-----
# From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-
# list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of Munna D
# Sent: 09 March 2004 13:20
# To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
# Subject: [xsl] XPath to get value of xmlns attribute
#
# Hi,
# Say I have an xml document beginning as follows:
# <!--extract for example-->
# <?xml version="1.0" encoding="utf-8"?>
# <feed version="0.2" xmlns="http://purl.org/atom/ns#";
# xmlns:tt="http://www.tt.org/ns#";>
# <!--end of extract-->
#
# I want to make a list of all atttributes (including namespace declaration
# ones). However, both of the templates below fail to pick up the xmlns and
# xmlns:tt attributes:
# <xsl:template match='@*'>
# <xsl:value-of select="name()"/>
# ='<xsl:value-of select="."/>'
# </xsl:template>
#
# and
#
# <xsl:template match="@*[starts-with(name(.),'xmlns')]" >
#
# <xsl:value-of select="name()"/>
# ='<xsl:value-of select="."/>'
# </xsl:template>
#
# Can someone please tell me how I can get these values?
#
# Thanks,
# Munna
#
#
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