I did not thought about this simple way of doing ! and indeed i sort my
datats according to an attributes node, i just did : <xsl:sort
select="@*[name()=$sortparam]"/>.
One more time Thanks David!
Matthieu.
-----Message d'origine-----
De : owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]De la part de
David
Carlisle
Envoyé : vendredi 5 mars 2004 16:32
À : xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Objet : Re: [xsl] sorting parameter ?
It work fine but I'm just wondering if there's not another way of doing it
using standard xsl.
the usual case, where the sortparam is not an arbitrary xpath but just
the name of a child element can be done by
<xsl:sort select="*[name()=$sortparam]"/>
Slightly more complicated expressions can easily be added to this
mechanism, essentially anything that involves a fixed length Xpath
without arbitrary predicates. But if you really want to be able to pass
in an arbitrary Xpath and sort on the result of that an extension
function is realistically the only option.
David
--
http://www.dcarlisle.demon.co.uk/matthew
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