Thank you,
thats the solution of my problem!
markus
concat() creates a string. You seem to be using it to construct an XPath
expression. You won't get a node-set unless you evaluate this XPath
expression, which you aren't even attempting to do.
Standard XSLT doesn't allow you to evaluate an XPath expression
constructed
dynamically as a string, but some products have an extension
(xx:evaluate())
that permits it.
But I don't think you need dynamic evaluation here. You can use the
standard
technique:
Select="$self_quirxi/globals/pers_datas/pers_data/*[name()=$qadmin_table]"
Michael Kay
# -----Original Message-----
# From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-
# list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of Markus Hanel
# Sent: 05 March 2004 07:21
# To: xsl mailinglist
# Subject: [xsl] concat - node set or a string
#
# I would like to write a node set that allows me to automatically show
the
# elements of a pers data.
# Therefore I defined 2 variables: self_quirxi and qadmin_table
# ...
# <xsl:variable name="self_quirxi"
# select="document('/qxml/quirxi.xml')/quirxi" />
# ...
# <xsl:variable name="qadmin_table" select="." /> selects surname,
# lastname,...
#
# Here I want to give out the node set, but it is only a string!
# <xsl:value-of
#
select="concat($self_quirxi,'/globals/pers_datas/pers_data/',$qadmin_table
# )" />
#
# Where is the bug?
# markus
#
#
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