RE: Using XPath to retrieve nodes by attribute.

This will give you quickbrownfox.
Let me know if I have misunderstood your question.

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/xml">
        <xsl:value-of select="CCC/DDD[(_at_)attrib='123'][1]"/>
        <xsl:value-of select="CCC/DDD[(_at_)attrib='456'][1]"/>
        <xsl:value-of select="CCC/DDD[(_at_)attrib='456'][2]"/>
</xsl:template>
</xsl:stylesheet>

-----Original Message-----
From: Manuel Reyes [mailto:Manuel(_dot_)Reyes(_at_)e-mis(_dot_)com] 
Sent: Thursday, April 29, 2004 9:11 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Using XPath to retrieve nodes by attribute.

Hello all,

I have the following XML document:

<xml>
        <AAA>foo</AAA>
        <BBB>bar</BBB>
        <CCC>
                <DDD attrib="123">quick</DDD>
                <DDD attrib="456">brown</DDD>
                <DDD attrib="789">fox</DDD>
                <DDD attrib="123">jumped</DDD>
                <DDD attrib="456">lazy</DDD>
                <DDD attrib="789">dog</DDD>
        </CCC>
</xml>

If I run the following XPath query it returns the count of all nodes in
CCC that have an attrib value of "123":

xml/CCC/DDD[(_at_)attrib='123'] = 2

What I am trying to do now is retrieve a particular node based on the
position in the CCC node and its attribute, something like this:

xml/CCC/DDD[(_at_)attrib='123'][1] = quick
xml/CCC/DDD[(_at_)attrib='456'][1] = brown
xml/CCC/DDD[(_at_)attrib='456'][2] = lazy

This is based on information I found here:
http://www.w3schools.com/xpath/xpath_location.asp

Unfortunately this does work, can anybody tell me where I am going wrong

Thanks
Manuel



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