Thanks heaps for that Kenny. 8-)
Fyi, the final xslt template was this:
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0" indent="no"/>
<xsl:template match="/">
<myoutput>
<xsl:apply-templates/>
</myoutput>
</xsl:template>
<xsl:template match="mytag">
<xsl:element name="mytag">
<xsl:attribute name="duration">
<xsl:choose>
<xsl:when test="contains(@duration,
'days')">
<xsl:value-of
select="translate(@duration, '
days', '') * 8"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of
select="translate(@duration, '
hours','')"/>
</xsl:otherwise>
</xsl:choose>
</xsl:attribute>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
thanks
David.
--- Kenny Akridge <kenny(_at_)akridgefamily(_dot_)com> wrote:
I don't know how to do this in 2.0, but this works
for 1.1(I believe it is
1.1).
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<myoutput>
<xsl:apply-templates/>
</myoutput>
</xsl:template>
<xsl:template match="mytag">
<xsl:choose>
<xsl:when test="contains(@duration, 'days')">
<!-- translate ' days' to empty string, which leaves
with an int -->
<xsl:value-of select="translate(@duration, ' days',
'') * 24"/>
<br/>
</xsl:when>
<xsl:otherwise>
<!-- ditto on ' hours' -->
<xsl:value-of select="translate(@duration, '
hours',
'')"/>
<br/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
-----Original Message-----
From: David Buddrige [mailto:dbuddrige(_at_)yahoo(_dot_)com]
Sent: Wednesday, April 14, 2004 10:48 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] manipulating a property value
Hi all,
I have the following input document:
<?xml version="1.0" encoding="iso-8859-1"?>
<info>
<mytag duration="3 days" />
<mytag duration="4 days" />
<mytag duration="6 hours" />
<mytag duration="33 hours" />
<mytag duration="13 hours" />
<mytag duration="5 days" />
<mytag duration="3 hours" />
<mytag duration="23 hours" />
</info>
What I want to do, is to convert the output document
so that all duration values are in hours, and
without
specifying the units. So where a duration = "3
days",
I want to convert it to hours by multiplying it by
8,
and dropping the units identifier.
Thus
<mytag duration="5 days" />
becomes
<mytag duration="40"/>
And also
<mytag duration="6 hours"/>
becomes
<mytag duration="6"/>
The xslt template I have written to [attempt] to do
this is as follows:
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<myoutput>
<xsl:apply-templates/>
</myoutput>
</xsl:template>
<xsl:template match="mytag">
<xsl:choose>
<xsl:when test="@duration='*days'"><!-- need to
somehow strip off the 'days' and multiply remaining
value by 8 --></xsl:when>
<xsl:otherwise><!-- need to somehow strip off the
'hours' and return the remaining substring
--></xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
I note that XSLT 2.0 has regular expressions
available
that would make this alot easier - is there any way
to
do this with XSLT 1.x?
thanks heaps
David Buddrige
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