You haven't understood that XSLT is a functional language that doesn't allow
assignment to variables.
You'd better take a step back and explain the problem you want to solve,
rather than describing the way you would have solved it in a procedural
language.
Michael Kay
-----Original Message-----
From: Animesh Sharma [mailto:asharma(_at_)in(_dot_)firstrain(_dot_)com]
Sent: 01 April 2004 06:14
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Using XSl:Variable and XSL:if together.
Hi,
I want to declare a variable and use it in if statement.
I'm trying as follows.
<xsl:variable name="chkValue" select="'true'"/>
<xsl:if chkValue="true">
--perform some operation.
Change the value of variable name chkValue.
<xsl:variable name="chkValue" select="'false'"/>
</xsl:if>
Please let me know where I'm going wrong in above implementation.
Thanks and regards,
Animesh
--+------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail:
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--+--