At 2004-05-28 12:24 -0700, Jon Steeves wrote:
I have an xml file that contains a tag called <bit>. <bit> has two
attribute: type and status, so it often looks like this:
<bit type="a" status="b">bitinfo</bit>
I want to remove all status attributes when they appear (they are
optional), so that the result will look like this:
<bit type="a">bitinfo</bit>
Can anyone help me?
If you want to use XSLT to do this, then use an identity transformation
where you prescribe that the status attribute of bit elements adds nothing
in the construction of the result tree, while everything else reconstructs
itself in the result tree.
An example is below.
Note, however, you may be incurring a capacity and performance hit by using
XSLT for such a simple transform ... you may wish to use a program with a
SAX interface instead because of a smaller footprint and faster execution.
I hope this helps.
........................... Ken
T:\ftemp>type jon.xml
<?xml version="1.0" encoding="iso-8859-1"?>
<bits>
<bit type="a" status="b">bitinfo</bit>
<bit type="b" status="c">bitinfo</bit>
<bit type="d">bitinfo</bit>
<bit status="e">bitinfo</bit>
<bit type="f" status="g">bitinfo</bit>
</bits>
T:\ftemp>type jon.xsl
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:template match="bit/@status"/><!--add nothing to the result for these-->
<xsl:template match="@*|node()"><!--identity for all other nodes-->
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
T:\ftemp>saxon jon.xml jon.xsl
<?xml version="1.0" encoding="utf-8"?><bits>
<bit type="a">bitinfo</bit>
<bit type="b">bitinfo</bit>
<bit type="d">bitinfo</bit>
<bit>bitinfo</bit>
<bit type="f">bitinfo</bit>
</bits>
T:\ftemp>
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