-----Original Message-----
From: Animesh Sharma [mailto:asharma(_at_)in(_dot_)firstrain(_dot_)com]
Hi,
I have to remove a particular attribute (in following example it
is "href") from all the ChildNodes of the particular node.
I tried to write template something as follows:
<xsl:template
match="//body/namespace/form/snip/csf/td[position()=1]/table[posit
ion()=2]">
<xsl:apply-templates select="@*"/>
<xsl:attribute name="href"/>
AFAIK, xsl:attribute is not a self-closing element, so if you really want to
create an empty href attribute, at least there should be
<xsl:attribute name="href"></xsl:attribute>
Although, I'm not sure whether this will work... (haven't needed or tested
anything like it)
If you just want to omit the href attribute from being output, you have two
options:
For both: remove the 'empty' xsl:attribute element you specified above. It
serves no purpose.
1. replace <xsl:apply-templates select="@*" /> by
<xsl:apply-templates select="@*[not(name()='href')]" />
2. keep the current form of the apply-templates instruction, and define a
null template matching @href, like <xsl:template match="@href" />
Hope this helps!
Greetz,
Andreas