<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xhtml="http://www.w3.org/1999/xhtml";>
[snip]
I want to parse it and get the result as
a HTML page.
I parse it via msxsl parser, but I get this error
D:\deepak\buildProcess_2\_tools>msxsl test.xhtml
test.xsl -o test.html
Error occurred while parsing document.
Code: 0xc00ce50a
URL:
file:///D:/deepak/buildProcess_2/_tools/test.xhtml
Line: 2
Column: 70
The character '>' was expected.
...
Can some one suggest some solution.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
^^^
xmlns:xhtml="http://www.w3.org/1999/xhtml";>
^^^
Remove the ';'
You only want whitespace between attribute values - definitely no
semi-colons!