RE: problem using self::node() in for-each

Without studying your logic in detail,

inf_source_id = ./inf_source_id

is obviously wrong because it means the same as

inf_source_id = inf_source_id

I suspect you want

 inf_source_id = current()/inf_source_id

Michael Kay

-----Original Message-----
From: Garrett Hynes [mailto:garretthynes(_at_)hotmail(_dot_)com] 
Sent: 21 May 2004 16:24
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] problem using self::node() in for-each


I have an XML document with the following structure:

XML Input

<root>
    <information type="source">
        <instance>
            <inf_type>source</type>
            <inf_source_id>1</id>
            <inf_name>Source 1</name>
        </instance>
        <instance>
            <inf_type>source</type>
            <inf_source_id>2</id>
            <inf_name>Source 2</name>
        </instance>
    </information>
    <information type="info">
        <instance>
            <inf_type>info</type>
            <inf_source_id>2</source_id>
            <inf_text>Information 1</text>
        </instance>
        <instance>
            <inf_type>info</type>
            <inf_source_id>1</source_id>
            <inf_text>Information 2</text>
        </instance>
        <instance>
            <inf_type>info</type>
            <inf_source_id>1</source_id>
            <inf_text>Information 3</text>
        </instance>
        <instance>
            <inf_type>info</type>
            <inf_source_id>2</source_id>
            <inf_text>Information 4</text>
        </instance>
        <instance>
            <inf_type>info</type>
            <inf_source_id>2</source_id>
            <inf_text>Information 5</text>
        </instance>
        <instance>
            <inf_type>info</type>
            <inf_source_id>1</source_id>
            <inf_text>Information 6</text>
        </instance>
    </information>
</root>

The inf_source_id in the <information type="info"> refers to the 
inf_source_id in the <information type="source">
i.e. Information 1 has inf_source_id of 2 meaning it came 
from Source 2.

I'm trying to output all the inf_text using xsl:for-each 
along with the name 
of the source it has a reference to through inf_source_id.

e.g.

Information 1 - Source 2
Information 2 - Source 1
Information 3 - Source 1
Information 4 - Source 2
Information 5 - Source 2
Information 6 - Source 1


However, I can't get the XPath expression to select the 
correct source node 
using the inf_source_id from the current node to work.
I've used this method before except not in <xsl:for-each> and 
it works fine.


XSLT

<xsl:template name="handleInformation">

    <xsl:variable name="info" 
select="/root/information/instance[inf_type='info']"/>

    <xsl:for-each select="$info">

        <xsl:variable name="inf_source" 
select="/root/information/instance[inf_type = 'source' and 
(inf_source_id = 
./inf_source_id)]/inf_name"/>

        <xsl:call-template name="printInformation">
            <xsl:with-param name="source" select=$inf_source"/>
            <xsl:with-param name="text" select=./inf_text"/>
        </xsl:call-template>

    </xsl:for-each>

</xsl:template>

Thanks,

Garrett

_________________________________________________________________
Help STOP SPAM with the new MSN 8 and get 2 months FREE*  
http://join.msn.com/?page=features/junkmail


--+------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: 
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--+--