It isn't clear what you expect your output to look like. If it is this:
test1::test2;;:|*|:
test3::test4;;:|*|:
Then then replace the contents of your stylesheet with these two templates:
<xsl:template match="/a">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="b">
<xsl:value-of select="c1" />::<xsl:value-of select="c2"/>;;:|*|:
</xsl:template>
If that isn't the output you want, then submit an example.
By the way, the bare <b> in the middle of your document makes it not a
well-formed XML document. You will have to clean up the input before anything
will work.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Dylan Barber <dylan(_dot_)barber(_at_)earthlink(_dot_)net>
Sent: Tue, 11 May 2004 11:02:22 -0500 (GMT-05:00)
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Simple XSL but having problems
Here is my xml layout
<a>
<b>
<c1>test1</c1>
<c2>test2</c2>
</b>
<b>
<b>
<c1>test3</c1>
<c2>test4</c2>
</b>
</a>
and i want to show c1 and c2 so i have this
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:for-each select="a/b">
<xsl:value-of select="c1"/>
::
<xsl:value-of select="c2"/>
;;
</xsl:for-each>:|*|:
</xsl:template>
</xsl:stylesheet>
however all i get is :|*|:
what did i do wrong (please no rebukes I am trying to understand this and I
think this structure should work its easy enough)
Thanks !!!!!
---------------------------------------------------------------------------------------------
Dylan Barber