Hi Sam,
Following is an identity transform which outputs XML
exactly same as the input XML.
Regards,
Mukul
How do I write a template match so that all the
output
XML looks exactly like the input XML.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:copy-of select="@* | node()" />
</xsl:template>
</xsl:stylesheet>
Thanks
Sam
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