xsl-list
[Top] [All Lists]

Re: How to copy parts of an var into another ?

2004-06-18 11:15:13
in XSL 1.0 the nodes created in a variable are not accessable in this
way. Look into the node-set() extension element.

Josh

On Fri, 18 Jun 2004 11:18:24 +0200, Jan Kohnert 
<j(_dot_)kohnert(_at_)swisslab(_dot_)de> wrote:

Hello List,

I have a var:

<xsl:variable name="foo">
       <item name="a item">
               <value>1</value>
       </item>
       <item name="another item">
               <value>2</value>
       </item>
</xsl:variable>

at one point in the stylesheet, I want so select one part of the var. That
is Necessary because in reality the var is MUCH bigger, and I want to avoid
using Xpathes from here to moscow each time...

I tried:

<xsl:variable name="partoffoo">
       <xsl:value-of select="$foo/item[(_at_)name = 'a item']"/>
</xsl:variable>

And tried to get the value by using:

<xsl:value-of select="$partoffoo/item/value"/>

to get the item of foo that has the name attribute "a item".
But it did not work.

Important is, that I also want to get every node that is child of the
selected <item>.

I tried copy and copy-of, but only got the var copied into the output
document.

Is there a way to solve this problem?

Thanks!

--+------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: 
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--+--




<Prev in Thread] Current Thread [Next in Thread>