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Re: Passing empty parameters discard parameters default value

2004-06-16 11:51:20
Hi Michal,

The problem is that you ARE passing a parameter to mytemplate_impl. It
might eventually be empty, but it still counts as a parameter, and
thus no default value is used... (after all, one can imagine cases
where passing an empty nodeset as a parameter has a semantical
meaning)

A possible work-around is:

<xsl:template name="mytemplate">
  <xsl:param name="p"/>
  <xsl:call-template name="mytemplate_impl">
    // parameter is not passed if its empty
    <xsl:if test="$p">
      <xsl:with-param name="p" select="$p"/>
    </xsl:if>
  </xsl:call-template>
</xsl:template>

regards,
Thijs Janssen

On Wed, 16 Jun 2004 14:58:16 +0200, ĎURDINA Michal
<michal(_dot_)durdina(_at_)assetsoft(_dot_)sk> wrote:

Hello,

I am having problems with passing empty parameters (no with-param specified) 
that discard default values of parameters. When I am calling the template and 
passing no value I want the template to use its default value.

Example:

  <xsl:template name="mytemplate">
    <xsl:param name="p"/>
    <xsl:call-template name="mytemplate_impl">
      <xsl:with-param name="p" select="$p"/>
    </xsl:call-template>
  </xsl:template>

  <xsl:template name="mytemplate_impl">
    <xsl:param name="p">default p</xsl:param>
    p = <xsl:value-of select="$p"/>
  </xsl:template>

When calling:
    <xsl:call-template name="mytemplate_impl"/>
the result is:
        p = default p
But when calling
    <xsl:call-template name="mytemplate"/>
the result is:
        p =

what is wrong in my case, becase I did not supplied any value to parameter $p 
so I want to see its default value. I know that I can declare the same 
default value in template "mytemplate" , but then I will have the same value 
in more than one place and that's not good when I will need to change it.

Is there any workaround for my problem?

Thank you,
Michal