Hi Michal
You are suppressing the default value by passing your template a parameter
with no value.
An easy solution would be to not pass a parameter if you have nothing to
pass.
<xsl:if test="$p"> etc
or to have a default value for the upstream template
<xsl:template name="mytemplate">
<xsl:param name="p" select="'Default P'"/>
<xsl:call-template name="mytemplate_impl">
<xsl:with-param name="p" select="$p"/>
</xsl:call-template>
</xsl:template>
Cheers
Rod
-----Original Message-----
From: DURDINA Michal [mailto:Michal(_dot_)Durdina(_at_)assetsoft(_dot_)sk]
Sent: 16 June 2004 13:58
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Passing empty parameters discard parameters default value
Hello,
I am having problems with passing empty parameters (no with-param specified)
that discard default values of parameters. When I am calling the template
and passing no value I want the template to use its default value.
Example:
<xsl:template name="mytemplate">
<xsl:param name="p"/>
<xsl:call-template name="mytemplate_impl">
<xsl:with-param name="p" select="$p"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="mytemplate_impl">
<xsl:param name="p">default p</xsl:param>
p = <xsl:value-of select="$p"/>
</xsl:template>
When calling:
<xsl:call-template name="mytemplate_impl"/>
the result is:
p = default p
But when calling
<xsl:call-template name="mytemplate"/>
the result is:
p =
what is wrong in my case, becase I did not supplied any value to parameter
$p so I want to see its default value. I know that I can declare the same
default value in template "mytemplate" , but then I will have the same value
in more than one place and that's not good when I will need to change it.
Is there any workaround for my problem?
Thank you,
Michal
PS: If you want to have full pricture why I need this default parameter
mechanism, here it is:
I have hierarchy of importing stylesheets and I try to simulate polymorphism
for named templates via shadowing of "interface" templates and by calling
"implementation" templates.
library.xsl:
<!-- interface template -->
<xsl:template name="mytemplate">
<xsl:param name="p"/>
<xsl:call-template name="mytemplate_impl">
<xsl:with-param name="p" select="$p"/>
</xsl:call-template>
</xsl:template>
<!-- implementation template -->
<xsl:template name="mytemplate_impl">
<xsl:param name="p">default p</xsl:param>
p = <xsl:value-of select="$p"/>
</xsl:template>
customized-library.xsl:
<xsl:import href="library.xsl"/>
<!-- interface template -->
<xsl:template name="mytemplate">
<xsl:param name="p"/>
<b>
<xsl:call-template name="mytemplate_impl">
<xsl:with-param name="p" select="$p"/>
</xsl:call-template>
</b>
</xsl:template>
user-stylesheet.xsl:
<xsl:include href="customized-library.xsl"/>
...
<xsl:template match="/">
<xsl:call-template name="mytemplate"/>
</xsl:template>
user-input.xml:
<?xml-stylesheet type="text/xsl" href="user-stylesheet.xsl"?>
<root/>
required output:
<b>p = default p</b>
actual output:
<b>p = </b>
I hope the idea is ok, developer of user-stylesheet.xsl can customize
templates from library.xsl that he/she uses in user-stylesheet.xsl. But I am
having the problem with passing empty parameter (no parameter) that discard
default value in original template.
-----------
Michal Ïurdina
ASSET Soft, a.s. / eBussiness Solutions
Ko¹ická 56, 821 08 Bratislava SLOVAK REPUBLIC
Phone: +421-2-50703-523
Fax: +421-2-50703-444
e-mail: michal(_dot_)durdina(_at_)assetsoft(_dot_)sk
http://www.assetsoft.sk
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