count((C|D)[1]/preceding-sibling::*) + 1
alternatively:
<xsl:for-each select="(C|D)[1]">
<xsl:number count="*"/>
</xsl:for-each>
Michael Kay
-----Original Message-----
From: Chen Yi [mailto:chen_yi36(_at_)hotmail(_dot_)com]
Sent: 06 June 2004 08:09
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
ALL,
For example,
<element>
<A/>
<B/>
<A/>
<C/>
<C/>
<D/>
</element>
I want to get the position first element whoes name is not A
and B, but C &
D. So it's 4 for this tree segment.
How can I write the xslt to figure out this ?
Thanks,
Chen Yi
_________________________________________________________________
免费下载 MSN Explorer: http://explorer.msn.com/lccn/
--+------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail:
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--+--