Hi Stephen,
I would have written something like this -
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:template match="/root">
<html>
<head>
<title/>
</head>
<body>
<table>
<tr>
<xsl:apply-templates select="menu[(_at_)ref =
'main_menu']/item"/>
</tr>
</table>
</body>
</html>
</xsl:template>
<xsl:template match="menu/item">
<xsl:call-template name="x-page">
<xsl:with-param name="resource"
select="@resource"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="x-page">
<xsl:param name="resource"/>
<xsl:variable name="x-name"
select="/root/page[(_at_)about = $resource]/name"/>
<xsl:variable name="y-name"
select="/root/category[(_at_)about = $resource]/name"/>
<td>
<a href="{$resource}">
<xsl:value-of select="$x-name"/><xsl:value-of
select="$y-name"/>
</a>
</td>
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
--- Stephen Tredrea <stephen(_dot_)tredrea(_at_)com-du-it(_dot_)com>
wrote:
Thanks Mukul for your response (and showing me how
to use {} - that's new to
me). Unfortunately your solution doesn't cater for
instances where:
a) an item in the menu is not a 'page', or
b) only a selection of resources constitute the
menu
...which is why I want to build the menu from the
menu node.
My apologies for providing an insufficient sample,
here's alternative xml:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<menu ref="main_menu">
<item resource="/"/>
<item resource="/who_we_are"/>
<item resource="/contact_us"/>
<item resource="/mulberries"/>
</menu>
<page about="/">
<name>Home</name>
</page>
<page about="/who_we_are">
<name>About us</name>
</page>
<page about="/contact_us">
<name>Contact us</name>
</page>
<page about="/disclaimer">
<name>Disclaimer</name>
</page>
<category about="/mulberries">
<name>Top fruit</name>
</category>
</root>
Note that in this sample I don't want 'Disclaimer'
in the menu.
This XSL below works but... I think it's clunky and
I don't understand why
the simpler version I provided in my prior example
doesn't work.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:apply-templates
select="//menu[(_at_)ref='main_menu'" mode="main_menu"
/>
</xsl:template>
<xsl:template match="menu" mode="main_menu">
<table>
<tr>
<xsl:apply-templates select="item" />
</tr>
</table>
</xsl:template>
<xsl:template match="item">
<xsl:param name="resource"><xsl:value-of
select="@resource"
/></xsl:param>
<xsl:apply-templates select="/root/*[(_at_)about =
$resource]"
mode="menu_item" />
</xsl:template>
<xsl:template match="*" mode="menu_item">
<td>
<a href="{(_at_)about}">
<xsl:value-of select="name"/>
</a>
</td>
</xsl:template>
</xsl:stylesheet>
Regard, Stephen
-----Original Message-----
From: Mukul Gandhi [mailto:mukul_gandhi(_at_)yahoo(_dot_)com]
Sent: 06 June 2004 10:02 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Recursive selection, elegantly
Hi Stephen,
Given the XML -
<?xml version="1.0" encoding="UTF-8"?>
<root>
<menu ref="main_menu">
<item resource="/"/>
<item resource="/who_we_are"/>
<item resource="/contact_us"/>
<item resource="/disclaimer"/>
</menu>
<page about="/">
<name>Home</name>
</page>
<page about="/who_we_are">
<name>About us</name>
</page>
<page about="/contact_us">
<name>Contact us</name>
</page>
<page about="/disclaimer">
<name>Disclaimer</name>
</page>
</root>
The following XSL -
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:template match="/root">
<html>
<head>
<title/>
</head>
<body>
<table>
<tr>
<xsl:apply-templates select="page"/>
</tr>
</table>
</body>
</html>
</xsl:template>
<xsl:template match="page">
<td>
<a href="{(_at_)about}">
<xsl:value-of select="name"/>
</a>
</td>
</xsl:template>
</xsl:stylesheet>
produces output -
<html>
<head>
<title></title>
</head>
<body>
<table>
<tr>
<td><a href="/">Home</a></td>
<td><a href="/who_we_are">About us</a></td>
<td><a href="/contact_us">Contact us</a></td>
<td><a href="/disclaimer">Disclaimer</a></td>
</tr>
</table>
</body>
</html>
Regards,
Mukul
--- Stephen Tredrea <stephen(_dot_)tredrea(_at_)com-du-it(_dot_)com>
wrote:
Any suggestion on getting this to work? I can do
it
in four steps but not in
three as attempted here!
Thanks, Stephen
XML (snippet):
<menu ref="main_menu">
<item resource="/" />
<item resource="/who_we_are" />
<item resource="/contact_us" />
<item resource="/disclaimer" />
</menu>
<page about="/">
<name>Home</name>
</page>
<page about="/who_we_are">
<name>About us</name>
</page>
...etc...
XSL (snippet):
<xsl:template match="/">
<xsl:apply-templates
select="//menu[(_at_)ref='main_menu'" mode="main_menu"
/>
</xsl:template>
<xsl:template match="menu" mode="main_menu">
<table>
<tr>
<xsl:apply-templates select="//*[(_at_)about =
item/resource]"
mode="menu_item" />
</tr>
</table>
</xsl:template>
<xsl:template match="*" mode="menu_item">
<td>
<xsl:element name="a">
<xsl:attribute name="href"><xsl:value-of
select="@about"
/></xsl:attribute>
<xsl:value-of select="name" />
</xsl:element>
</td>
</xsl:template>
Required HTML:
<table>
<tr>
<td><a href="/">Home</a></td>
<td><a href="/who_we_are">About us</a></td>
...etc...
</tr>
</table>
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