In XSLT 2.0:
<a href="{(link[matches(.,'^http://')],
link[matches(.,'^ftp://')])[1]}">title</a>
In 1.0:
<a>
<xsl:attribute name="href">
<xsl:choose>
<xsl:when test="link(starts-with(., 'http://'))">
<xsl:value-of select="link(starts-with(., 'http://'))"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="link(starts-with(., 'ftp://'))"/>
</xsl:otherwise>
</xsl:choose>
</xsl:attribute>
title
</a>
-----Original Message-----
From: Dionylon Briones [mailto:lon(_at_)designbytes(_dot_)com(_dot_)ph]
Sent: 31 July 2004 00:51
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] newbie question
hello everyone,
i'm new to XSL and need help with this problem:
choose a link for the title, base on the following conditions:
1. if the value of the link node has 'http://' string
2. if there's no 'http://' string get the value of the link
node that
contains 'ftp://' string
output should be: <a href="selected link">title</a>
thanks
<?xml version="1.0" encoding="ISO-8859-1" standalone="yes"?>
<record>
<data>
<link>http://www.link1.com</link>
<link>3csbv</link>
<link>ftp://link2.com</link>
<link>http://www.link3.com</link>
<title>title</title>
</data>
<data>
<link>45csgh</link>
<link>invalid link</link>
<link>ftp://link1.com</link>
<title>title</title>
</data>
</record>
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