Hi Alain,
you can do something like this:
<xsl:variable name="n-rows" select="5"/>
<xsl:template match="/">
<html>
<head>...</head>
<body>
<table>
<tr>
<xsl:call-template name="td-recursive"/>
</tr>
</table>
</body>
</html>
</xsl:template>
<xsl:template name="td-recursive">
<xsl:param name="index" select="1"/>
<td>
<xsl:value-of select="info[$index]"/>
</td>
<xsl:if test="$index < $n-rows">
<xsl:call-template name="td-recursive">
<xsl:with-param name="index" select="$index + 1"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
HTH,
Anton Triest
<quote from="Alain ROY">
> Hi all,
>
> I want to make a table which may contain always the same number of rows
(actually 5 but this can change later).
> I want to fill this table with nodes values (let's say "info" for example).
If there are less "info" nodes than the number of
rows
> I chose for my table, I want to complete it with empty rows. If there are
more "info" nodes than the number of rows of my table,
I
> want to fill the table with only the n firsts info nodes values (n=number
of rows of my table).
> To fill my table I made a template for the rows. So I'd like to make a loop
which will always call this template n times with a
> parameter info[x] x=1..n
>
> What's the best way to do that ?
>
> Regards
> AR
</quote>