You mean exslt.org, I think.
The node-set() function cannot be implemented using XSLT itself, it has to
be implemented by the vendor. All XSLT implementations that I know of
provide such a function, but it's sometimes in the vendor's namespace rather
than the EXSLT namespace.
Michael Kay
-----Original Message-----
From: Markus Hanel [mailto:markus(_dot_)hanel(_at_)gmx(_dot_)at]
Sent: 26 July 2004 10:58
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] using exsl:node-set()
hallo,
I make something wrong! I want to use the exsl:node-set()
function but at
www.exsl.org there is no download of the exsl.node-set.xsl
stylesheet. But
in the main download there are two stylesheets:
exsl.node-set.1.xsl and
exsl.node-set.2.xsl, but this not works.
markus
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:exsl="http://exslt.org/common";
extension-element-prefixes="exsl">
<xsl:import href="exsl.node-set.1.xsl" />
<xsl:import href="exsl.node-set.2.xsl" />
<xsl:template match="/">
<html>
<head><title></title></head>
<body>
<xsl:apply-templates select="./table" />
</body>
</html>
</xsl:template>
<xsl:template match="table">
<xsl:variable name="sorted-rows-rtf">
<xsl:for-each select="./row">
<xsl:sort select="sum(./cell/@points)" data-type="number"
order="descending" />
<xsl:copy-of select="." />
</xsl:for-each>
</xsl:variable>
<xsl:variable name="sorted-rows"
select="exsl:node-set($sorted-rows-rtf)/row" />
<xsl:value-of select="sum($sorted-rows[position() <=
4]/cell/@points)"
/>
</xsl:template>
</xsl:stylesheet>
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