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RE: Return position in for-each

2004-07-22 16:15:25
In general, move the "test" condition into a predicate in the select
expression of the xsl:for-each. Change

<xsl:for-each select="x">
  <xsl:if test="y">

to

<xsl:for-each select="x[y]">

In your example it's not quite so easy because you are defining a variable
before the <xsl:if>, and the variable itself accesses the position. I don't
understand your logic well enough at this time of night to suggest a
rewrite.

Incidentally, 

  <xsl:variable name="x"><xsl:value-of select="y"/></xsl:variable>

should in 99.99% of cases be rewritten

  <xsl:variable name="x" select="y"/>

Michael Kay 

-----Original Message-----
From: Karl J. Stubsjoen [mailto:karl(_at_)meetscoresonline(_dot_)com] 
Sent: 22 July 2004 23:46
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Return position in for-each

Hello,

A disadvantage to an xsl:for-each is that the position() 
increases by one
for each step.  so, if an xsl:if test validates the current 
step and says
"Yes apply templates for this step", "don't apply templates 
for this step",
and you are interested in a positiion which reflects the 
total number of
"YES" steps... well you have a problem.  Take into consideration this
for-each rule:

<xsl:for-each select="Entry">
<xsl:variable name="element_name"><xsl:value-of
select="concat('competitor_name_',position())"/></xsl:variable>
  <xsl:if 
test="string($BROWSER_VARS//ELEMENT[(_at_)name=$element_name]/.)">
    <tr>

      <!-- [[[ HERE WE ADD A COLUMN THAT HAS AN INCREMENTING 
NUMBER ]]] -->
      <td><xsl:value-of select="concat(position(),'.')"/></td>

      <!-- [[[ HERE WE GET THE REST OF THE COLUMN DATA ]]] -->
      <xsl:apply-templates select="Element" mode="PRINTER_FRIENDLY">
         <xsl:with-param name="position"><xsl:value-of
select="position()"/></xsl:with-param>
      </xsl:apply-templates>
    </tr>
  </xsl:if>
</xsl:for-each>


Is there a work-around, or another way to accomplish an 
incrementing number
for the TD?

Karl


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