Hi Alla,
Your implementation is read by the xslt processor and when it comes across
<xsl:output... it doesnt know that you want it to output <xsl:output... but
instead assumes you are declaring the <xsl:output../> element. As you probably
already know the <xsl:output element must be a direct child of
<xsl:stylesheet...> and cannot be inside of a template or anywhere after the
first xsl:template element is declared... The way to accomplish what you are
trying to do is to use the <xsl:element name="xsl:output"> and then add the
necessary attributes using <xsl:attribute name="method">xml</xsl:attribute> etc...
Hope this helps!
Belkin, Alla wrote:
Hello,
I am using a stylesheet for modifications of the input xml file to the
different format of the xml file.
My output file should have a document element, the same as in the input
file. How to copy a document element? I can have input XMLs with
different document elements. I tried to do something like this, but it
doesn't work:
<xsl:choose>
<xsl:when test="count(//Delete) > 0">
<xsl:output method="xml"
doctype-system="http://delete.dtd"/>
</xsl:when >
<xsl:when test="count(//Delete) = 0">
<xsl:output method="xml"
doctype-system="http://update.dtd"/>
</xsl:when>
</xsl:choose>
Please, help
Thank you,
Alla Belkin
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