xsl-list
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RE: finding position in list of siblings

2004-07-09 12:13:00
Try this template:

<xsl:template match="BROTHER">
   <xsl:value-of select="count(preceding-sibling::*[name()='BROTHER')" />
</xsl:template>

--
Charles Knell
cknell(_at_)onebox(_dot_)com - email