Ranjan,
But I'm not sure this is going to work (have you tested it?):
count(connectivity//*[(_at_)*[not(local-name() = 'sharedsource')]])
for the stated requirement
how to find out [the] number of elments which [do] not have a particular
attribute?
Parsing the XPath into English ...
count()
counts a set of nodes
connectivity
expands to child::connectivity ('connectivity' child elements of the
context node) ... this could be what you want, depending on the input and
the context node being matched
connectivity//*
expands to child::connectivity/descendant-or-self::node()/*
namely any element descendant of the 'connectivity' children
[(_at_)*]
"which has an attribute"
[not(local-name() = 'sharedsource')]
"whose local name is not 'sharedsource'"
In other words, the expression returns the count of all descendants of
'connectivity' children that have an attribute whose local name is not
'sharedsource'.
This is different from all elements that have no 'sharedsource' attribute.
To cut to the chase, the latter would be
count(//*[not(@sharedsource)])
which returns the count of all element descendants of the root that have no
'sharedsource' attribute.
Its long-syntax form is
count(/descendant-or-self::node()/*[not(attribute::sharedsource)])
Cheers,
Wendell
At 08:36 AM 7/7/2004, 'twas written:
> <xsl:variable name="sharedcount1"
> select="count(connectivity//*[(_at_)*[not(local-name() =
> 'sharedsource')]])"/>
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Wendell Piez
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