Try:
<xsl:choose>
<xsl:when test="REGION [(_at_)NAME='VA']">
<xsl:value-of select="REGION [(_at_)NAME='VA']"/>
</xsl:when>
<xsl:otherwise>0.0</xsl:otherwise>
</xsl:choose>
From: michael(_dot_)s(_dot_)eberhart(_at_)verizon(_dot_)com
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Printing a value if an attribute does not exist
Date: Mon, 23 Aug 2004 23:04:11 -0400
How do you check for the existence of an attribute?
<TIER>
<REGION NAME="CT">89</REGION>
<REGION NAME="MD">135</REGION>
</TIER>
What I want to say is:
If region[(_at_)name="VA"] exists
print value of region[(_at_)name="VA"]
else
print "0.0"
It is also possible that there will be no REGION elements
<TIER>
</TIER>
I would still want to say:
If region[(_at_)name="VA"] exists
print value of region[(_at_)name="VA"]
else
print "0.0"
Thanks
Mike
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