No, this can only be done using an extension function (or some very tortuous
low-level code). This is true even in XSLT 2.0/XPath 2.0, which supports the
xs:base64Binary data type but doesn't provide any function to get from a
sequence of octets to a base64Binary value.
I found that the following works with my current build of Saxon 8.1:
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0"
xmlns:b64="net.sf.saxon.value.Base64BinaryValue"
exclude-result-prefixes="b64">
<xsl:template match="/">
<out>
<a><xsl:value-of
select="b64:new(string-to-codepoints('Müller'))"/></a>
</out>
</xsl:template>
</xsl:stylesheet>
Unfortunately it doesn't work with Saxon 8.0 because the mapping of an XPath
sequence of integers to a Java byte[] array isn't picked up: a different
constructor is selected instead. The basic code is there in Saxon, but
you'll have to write a Java wrapper method to invoke it.
I'll probably package this as a documented extension function in due course.
Michael Kay
-----Original Message-----
From: Michael Wiedmann [mailto:michael(_dot_)wiedmann(_at_)detewe(_dot_)de]
Sent: 19 August 2004 10:05
To: XSL List
Subject: [xsl] Encoding base64 with XSLT
An XML based addressbook has to be converted to LDIF (LDAP Data
Interchange Format, RFC 2849) using an XSLT-stylesheet. LDIF does not
allow non-ASCII characters, they have to be base64-encoded.
E.g. given an element
<lastname>Müller</lastname>
has to be written like
sn:: TfxsbGVy
instead of simply:
sn: Müller
Is there any way to encode base64 with XSLT
Michael
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