Re: extract xpath locator

Hello,

I have written a recursive template to extract the XPath pointing to an element

                <xsl:template name="getPath">
                        <xsl:param name="node"></xsl:param>
                        <xsl:if test="$node">
                                <xsl:call-template name="getPath">
                                        <xsl:with-param name="node" 
select="$node/parent::*"></xsl:with-param>
                                </xsl:call-template>    
                                <xsl:text>/</xsl:text>
                                <xsl:variable name="name">
                                        <xsl:value-of 
select="name($node)"></xsl:value-of>
                                </xsl:variable>
                                <xsl:value-of select="$name"></xsl:value-of>
                        </xsl:if>
                </xsl:template>

This gives the hierarchy. Eg,

applied on <b> in:

        <doc>This is <i><b>a</b></i> test</doc>

it outputs "/doc/i"

But I cannot figure out how to compute the positions of nodes; applied on <b> 
in:

        <doc>This <i>i</i>s <i><b>a</b></i> test</doc>

of course, it still outputs "/doc/i", but I want to improve it to output 
"/doc/i[2]".

Since the context node is the <b> element, using 'position()' in the template 
returns its position(). I cannot tell the template that $node becomes the 
context node --maybe it's possible, but I don't know how. I have tried to 
"count(preceding-sibling::$name)", but saxon does not like it. I keep trying 
harder.

Thanks in advance for your help.

N. Mazziotta