I believed that the position() function should give me the
position number
of the node in the node set. But it appears to not being the
case. I don't
understand the result of this function (I use saxon to
process my xsl
transformation). It numbers my row nodes 2 by 2.
Can somebody explain me what I missed ?
In case you didn't get the message from previous answers, you have selected
a node sequence that contains element nodes alternating with whitespace-only
text nodes. Therefore, the element nodes are all in even-numbered positions.
Consider using xsl:strip-space to get rid of the whitespace-only text nodes.
Michael Kay