Michael PG wrote:
I still get empty parent nodes that are not filtered, since I left out
the info. that attribute filter is also present on the parent node. It
can also be empty or contain information.
How can I filter that away as well.
If you say you left out the info, does that mean you don't group
anymore, only filter? And in the example below, what do you want to do
with Article forename="John"? If you filter out the elements with
filter='food', the first Document will not be included. That would leave
out John too, although he has a filter='food'.
<Documents>
<Document id="0001" filter="">
<Article title="Mr"/>
<Article forename="John" filter="food"/>
<Article surname="Smith" filter=""/>
</Document>
<Document id="0002" filter="food">
<Article title="Dr"/>
<Article forename="Amy" filter=""/>
<Article surname="Jones" filter="food"/>
</Document>
</Documents>
The best solution depends on what exactly you want to do. If it's plain
filtering, a slight variation on the identity template would do:
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="*[(_at_)filter='food']"/>
</xsl:copy>
</xsl:template>
that would give:
<Documents>
<Document id="0002" filter="food">
<Article surname="Jones" filter="food"/>
</Document>
</Documents>
It might be a good idea to put the filter string in a global parameter:
<xsl:stylesheet ...>
<xsl:param name="filter" select="'food'"/>
...
<xsl:apply-templates select="*[(_at_)filter=$filter]"/>
If you still want to combine grouping and filtering, that's also possible:
<xsl:template match="Documents">
<Documents>
<xsl:for-each
select="Document[(_at_)filter=$filter]/Article[count(.|key('by-info',@info)[1])=1]">
<Document name="{(_at_)info}">
<xsl:copy-of
select="key('by-info',@info)[(_at_)filter=$filter]"/>
</Document>
</xsl:for-each>
</Documents>
</xsl:template>
Best regards,
Anton