The groups are numbered by counting left brackets: the 5th unescaped left
bracket starts group 5, regardless of where the closing brackets or are, and
regardless of other operators such as "|".
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Pawson, David [mailto:David(_dot_)Pawson(_at_)RNIB(_dot_)ORG(_dot_)UK]
Sent: 29 September 2004 08:23
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] regex grouping precedence.
http://www.w3.org/TR/xslt20/#element-matching-substring seems to say
little about how nested grouping is numbered.
(...) (....) ( ....)
gives regex-group (1,2,3) OK.
(...) (....)| ( ....)
Is the third group counted as two due to the alternates?
or still 3?
(...) ( (..)(.).) ( ....)
1 2 3 4 5
is how I would expect to number them,
but I'm totally unsure.
Using xslt 2 to parse a plain text file;
Input string
500748,500748 ,Set My People Free
regex
<xsl:for-each select='tokenize($f, "[\r]?\n")'>
<r>
<xsl:analyze-string flags="ix"
regex="([0-9]{{6}})
(,,)|(,([0-9]{{6}})\p{{Zs}}+,(.*))$"
select=".">
<xsl:matching-substring>
<bibno><xsl:value-of select="regex-group(1)"/></bibno>
<ck><xsl:value-of
select="normalize-space(regex-group(4))"/></ck>
<ttl><xsl:value-of
select="normalize-space(regex-group(5))"/></ttl>
</xsl:matching-substring>
<xsl:non-matching-substring>
<n><xsl:value-of select="."/></n>
</xsl:non-matching-substring>
</xsl:analyze-string>
</r>
</xsl:for-each>
output is
<n>500748</n>
<bibno/>
<ck>500748</ck>
<ttl>Set My People Free</ttl>
Regards DaveP.
**** snip here *****
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