First:
The doctype I am trying to use looks like this:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd";>
I don't know how to get the Doctype to look like this in XSLT - current
form is:
<xsl:output Method="html" encoding="UTF-8" doctype-public="-//W3C//DTD
XHTML 1.0 Transitional//EN" />
I don't know where to add: "http://www.w3.org/TR/html4/strict.dtd"; to the
above.
Second:
I am now using the ADODB Stream method to stream the result of the
transformation correctly and then perform an response.binarywrite.
However, lets say I'm interested in XHTML results so I add the following
namespace decleration to the stylesheet:
xmlns="http://www.w3.org/1999/xhtml";
The encoding I specified in the xsl:output gets lost is this normal?
Third:
This is illegal? (Doctype decleration in top-level node match)
<xsl:template match="/">
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd"/>
(again, this is the doctype form I am trying to achieve)
Thanks,
Karl