Firstly, thanks for all the help.
I'm including my solution here so others might benefit.
<?xml version="1.0" encoding="UTF-16"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="xml" />
<xsl:strip-space elements="*"/>
<xsl:template match="//parent/myContent//@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="@*[.='']"/>
<xsl:template match="//parent/myContent/*[.='' and not(attribute::*)]"/>
</xsl:stylesheet>
Cheers
Bryan
From: "Michael Kay" <mhk(_at_)mhk(_dot_)me(_dot_)uk>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: RE: [xsl] Empty nodes AND attributes stripping - I'm so lost
Date: Thu, 2 Sep 2004 17:21:43 +0100
Except that you also appear to define an element as being empty if all its
children are empty, unless it is a myContent element. But David has given
you the principle: once you sort out what the rules are, writing them in
XSLT isn't difficult.
You can match an element that is empty in the sense above with
match="*[not(.//text())]"
provided you have used
<xsl:strip-space elements="*"/>
to remove the whitespace text nodes.
Michael Kay
> -----Original Message-----
> From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk]
> Sent: 02 September 2004 16:52
> To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
> Subject: Re: [xsl] Empty nodes AND attributes stripping - I'm so lost
>
>
> just copy the identity transform from the xslt spec:
>
>
> <xsl:template match="@*|node()">
> <xsl:copy>
> <xsl:apply-templates select="@*|node()"/>
> </xsl:copy>
> </xsl:template>
>
> then add a template to zap empty attributes:
>
> <xsl:template match="@*[.='']"/>
>
> and a template to zap empty elements
>
>
> <xsl:template match="*[not(node())]"/>
>
> David
>
>
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