Thanks.
What I have learned from this forum is to be very precise when making an
example to try to simplify a real life situation.
In the real case the tags <A> to <E> are more like <Order1> to <Order5> and
<a> to <e> are like <Show1> to <Show5>. That will make the use of uppercase
/ lowercase functions useless.
<Root>
</...>
<Show1>10</Show1>
<Show2>20</Show2>
<Show3>30</Show3>
<Show4>40</Show4>
<Show5>50</Show5>
</...>
...
...
<Order1>3</Order1>
<Order2>5</Order2>
<Order3>1</Order3>
<Order4>2</Order4>
<Order5>4</Order5>
</..>
</Root>
And it needs to be:
<no>30</no>
<no>40</no>
<no>10</no>
<no>50</no>
<no>20</no>
Thanks in advance.
Kenny Bogoe
Hi,
I have this structure where the content of tags <A> to <E> have to determine
the order of tag-content <a> to <e>. The result needs to be as shown below.
I can manage to make a stylesheet with an <xsl:if> for each <A> to <E>
asking whether the number is 1, 2, 3, 4 or 5, but I am sure there must be a
simpler way to do this. I can not use position() since the position af the
tags can change in the structure.
<Root>
<a>10</a>
<b>20</b>
<c>30</c>
<d>40</d>
<e>50</e>
...
...
<A>3</A>
<B>5</B>
<C>1</C>
<D>2</D>
<E>4</E>
</Root>
Result I need:
<no>30</no> <!-- C = 1 has to be first with the value of c (which is 30) -->
<no>40</no>
<no>10</no>
<no>50</no>
<no>30</no>
Thanks.
Kenny Bogoe
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