A classic grouping problem: see
http://www.jenitennison.com/xslt/grouping
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Ralf Heydenreich [mailto:rheydenr(_at_)HTWM(_dot_)De]
Sent: 29 October 2004 13:53
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] counting equal entries
Hi all,
I try to create an index page from a document. The idea behind is to
collect a certain word and list it with *all* occurences in the
document, like
foo .... 12, 23, 45
bar .... 2, 5, 88
and so on. I have a XML document which contains entries with different
classes (Java classes).
I have a XSL stylesheet which collects all entries in a sorted order.
But there is one separate entry for each occurence:
foo ... 12
foo ... 23
foo ... 45
bar ... 2
and so on.
Code follows:
<xsl:for-each select="key('index-key', $lower-alphabet)">
<xsl:sort select="@name" case-order="lower-first"/>
<xsl:call-template name="display-index-item">
<xsl:with-param name="item" select="." />
</xsl:call-template>
</xsl:for-each>
The $lower-alphabet is only a variable containing all lower letters.
How can I pass an indicator to the template "display-index-item" where
I can decide if an entry has the same name as the previous one?
TIA,
Ralf.
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