<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:my="urn:mine" extension-element-prefixes="my">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<my:priorities>
<my:p desc="Bed & Breakfast"/>
<my:p desc="Bed & Breakfast (child)"/>
<my:p desc="Half Board"/>
<my:p desc="Half Board (child)"/>
<my:p desc="Full Board"/>
<my:p desc="Full Board (child)"/>
</my:priorities>
<xsl:variable name="priorities"
select="document('')/xsl:stylesheet/my:priorities/my:p"/>
<xsl:template match="/supplements">
<supplements>
<xsl:apply-templates select="supp">
<xsl:sort
select="count($priorities[(_at_)desc=current()/supp-desc]/preceding::*)"/>
</xsl:apply-templates>
</supplements>
</xsl:template>
<xsl:template match="supp">
<xsl:copy-of select="."/>
</xsl:template>
</xsl:stylesheet>
This will sort the supp elements according to the position in
my:priorities.
Not found supp-desc strings will have priority 0 so they will be first
in output.
Of course you can also put the priorities in a separate file and select
it like
<xsl:variable name="priorities"
select="document('priorities.xml')/my:priorities/my:p"/>
Cheers,
Anton
Kevin Bird wrote:
Hi David
Thanks for the answer(s). It is not a straighforward sort. Looking at in
terms of priority:
Bed & Breakfast --> priority 1
Bed & Breakfast (child) --> priority 2
Half Board --> priority 3
Half Board (child) --> priority 4
Full Board --> priority 5
Full Board (child) --> priority 6
All other <supp> nodes are output before the priority ones above (in
document order).
Kind regards.
--
Kevin