I'm trying to understand...
Given the XML document below with 2 "person" nodes in it, if my XSL
document looks like this:
---------------------------------------------
<?xml version='1.0'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html" />
<xsl:param name="gender"/>
<xsl:param name="city"/>
<xsl:template match="/my_document">
<xsl:for-each select="person[$gender = '' or gender = '$gender']">
<p>Name: <xsl:value-of select="name"/></p>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
---------------------------------------------
1. if the value of parameter "gender" is the "default default" (""),
then what if anything will be displayed?
2. if parameter "gender" has a value of "Male", will "Name: Joe" be the
output?
I read in your (Michael's) book about the "or" only evaluating the 2nd
operand if the 1st operand is false. But I still don't quite understand
how the xpath select will be evaluated if the parameter has a "" value -
the first operand ($gender='') will then be true, which will essentially
make the xpath select="person[$gender='']" right? And I don't know how
xpath will interpret that.
Please straighten me out ;-)
TIA.
Hardy Merrill
mike(_at_)saxonica(_dot_)com 10/04/04 11:56AM >>>
Firstly, a stylsheet parameter always has a value. Let's suppose the
default
value is "$$$" (the "default default" is ""). Then you can write your
query
as
//item[$param = '$$$' or @field = $param]
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Hardy Merrill [mailto:HMerrill(_at_)dhcr(_dot_)state(_dot_)ny(_dot_)us]
Sent: 04 October 2004 16:10
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] newbie - parameters with/without values??
XSLT newbie alert.
I have an xml document with lots of nodes. I have some fields
(each with its own value) I'd like to use as "search"
criteria - normally I would pass the field values into the XSL
style sheet as parameters, and just reference the parameters.
But the kicker here is that the parameters may *** or may not ***
have values. If a parameter has a value, I want to include it in
an XPath select. If a parameter does NOT have a value, then I
don't want to include that parameter in the XPath select.
I've been trying to use variables to "build" an XPath expression
from the supplied parameters using "if test"s, but I'm not having
much luck since variables can only be given a value once, and their
scope is limited to the block in which they are declared.
Given this XML document:
<my_document>
<person>
<name>Joe</name>
<gender>Male</gender>
<city>Boston</city>
</person>
<person>
<name>Janice</name>
<gender>Female</gender>
<city>Denver</city>
</person>
</my_document>
can I build an XSL style sheet to take in parameters "gender" and
"city", which may or may not have values, and *build* an XPath
select expression that will find the right nodes?
I'm sure this is a trivial question, but being a newbie I'm having
trouble with it.
TIA.
Hardy Merrill
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