RE: XPatch: ancestor and count

Andrey,

I slightly modified the XSLT like that

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html"/>
<xsl:template match="menu">
  <table class="menu" border="1">
    <tr><td><xsl:value-of
select="count(ancestor::*)"/></td><td>&#xA0;</td></tr>
    <xsl:for-each select="descendant::menuitem">
     <tr><td><xsl:for-each select="ancestor::*">/<xsl:value-of
select="concat(local-name(), ' ', @title)"/></xsl:for-each></td><td>
     <xsl:value-of select="@title"/></td></tr>
    </xsl:for-each>
  </table>
</xsl:template>
</xsl:stylesheet>

I got consistent results with XalanJ, Saxon 6, Saxon 8, MSXML,
XslTransform.
        
0   
/menu                                   1 
/menu                                   2 
/menu /menuitem 2                       2.1 
/menu                                   3 
/menu /menuitem 3                       3.1 
/menu /menuitem 3                       3.2 
/menu /menuitem 3                       3.3 
/menu /menuitem 3                       3.4 
/menu /menuitem 3/menuitem 3.4  3.4.1 
/menu /menuitem 3/menuitem 3.4  3.4.2 
/menu /menuitem 3                       3.5 
/menu /menuitem 3                       3.6 
/menu /menuitem 3/menuitem 3.6  3.6.1 
/menu /menuitem 3/menuitem 3.6  3.6.2

You may try with LibXSLT to see what path comes out.

Ivan



> -----Original Message-----
> From: Andrey V. Elsukov [mailto:elsukov(_at_)rdu(_dot_)kirov(_dot_)ru]
> Sent: Friday, October 01, 2004 1:18 AM
> To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
> Subject: [xsl] XPatch: ancestor and count
>
> Hi,
>
> I have some XML file, for example:
> =======
> <menu>
>       <menuitem title="1"/>
>       <menuitem title="2">
>         <menuitem title="2.1"/>
>       </menuitem>
>       <menuitem title="3">
>         <menuitem title="3.1"/>
>         <menuitem title="3.2"/>
>         <menuitem title="3.3"/>
>         <menuitem title="3.4">
>               <menuitem title="3.4.1"/>
>               <menuitem title="3.4.2"/>
>         </menuitem>
>         <menuitem title="3.5"/>
>         <menuitem title="3.6">
>               <menuitem title="3.6.1"/>
>               <menuitem title="3.6.2"/>
>         </menuitem>
>       </menuitem>
> </menu>
> ======
> and XLS transform:
> ======
> <xsl:template match="menu">
>   <table class="menu">
>     <tr><td><xsl:value-of
select="count(ancestor::*)"/></td><td>&#xA0;</td></tr>
>     <xsl:for-each select="child::menuitem">
>      <tr><td><xsl:value-of select="count(.//ancestor::*)"/></td><td>
>      <xsl:value-of select="@title"/></td></tr>
>     </xsl:for-each>
>   </table>
> </xsl:template>
> ======
> In result the following:
> ======
> 1         - root element
> 2    1    - root, menu
> 3    2    - root, menu, menuitem "2"
> 5    3    - root, menu, menuitem "3", menuitem "3.4" and what???
> ======
> http://www.w3.org/TR/1999/REC-xpath-19991116 :
> * the ancestor axis contains the ancestors of the context node;
> the ancestors of the context node consist of the parent of context
> node and the parent's parent and so on;..
>
> * Function: number count(node-set)
> The count function returns the number of nodes in the argument
node-set.
> ======
> Why the result is 5? It should be equal 4, or not?
>
> PS. I use Perl-5.8.5 + LibXML + LibXSLT..
> --
> Best regards,
> Andrey V. Elsukov
>
>
>
>
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