Hi Matthew:
I think <xsl:value-of
select="/one/two[three/four[contains(text(),$nodeValue)]]"/>
will display the value on the out .It is not to set
the variable value. you need set the variable value on
the same line which you define variable
example:
<xsl:variable name="myvariable" value=""/>
on the xslt, you can't change variable since you
define it. so It is impossible for you to set the
variable value twice.
what you can do:
<xsl:param name="nodeValue">something</xsl:param>
<xsl:param name="valueSearch">false</xsl:param>
<xsl:choose>
<xsl:when test="$valueSearch='false'">
<xsl:variable name="initialResult"
select="/one/two[three/four[contains(text(),$nodeValue)]]"/>
</xsl:when>
<xsl:otherwise>
<xsl:variable name="initialResult"
select="/one/two[three/four[contains(text(),$nodeValue)]]"/>
</xsl:otherwise>
</xsl:choose>
<xsl:template match="/">
<xsl:apply-templates select="$initialResult"/>
</xsl:template>
--- Matthew Hailstone <mhailstone(_at_)novell(_dot_)com> wrote:
I'm trying to assign a variable a node-set that
depends on a parameter
passed into the stylesheet.
<xsl:param name="nodeValue">something</xsl:param>
<xsl:param name="valueSearch">false</xsl:param>
<xsl:variable name="initialResult">
<xsl:choose>
<xsl:when test="$valueSearch='false'">
<xsl:value-of
select="/one/two[three/four[contains(text(),$nodeValue)]]"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of
select="/one/two[three/four[contains(text(),$nodeValue)]]"/>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<xsl:template match="/">
<xsl:apply-templates select="$initialResult"/>
</xsl:template>
<xsl:template match="/one/two">
...
</xsl:template>
I get an error in oXygen saying, "Cannot process a
result tree fragment
as a node-set under XSLT 1.0"
Am I doing something wrong?
Thanks in advance. :)
Matthew
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