Thanks for you reply.
I don't know why but node matches don't work when I use the simple
syntax:
my-relation
instead of
node()[name(.)='my-relation'
Is there something wron with my xsl transformer?
R.
-----Original Message-----
From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk]
Sent: Dienstag, 30. November 2004 13:02
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Test for node name and attribute value
I am stuck with the following node set expression.
In an external document I want to find the element which name is
'anchor' and which attribute @name has the value
of the variable $anchor.
If I understand you correctkly you just want
<xsl:variable
name="anchor-node"select="$external-doc//anchor[(_at_)name=$anchor]"/>
I in your code fragments you seem to have switched to looking for name
my-anchor rather than anchor.
3 <xsl:variable name="anchor-node" select="$external-doc//node()[name()
= 'my-anchor' and @name = $anchor]" />
that is legal but there is no need to select all nodes withg node() then
filter out those with name my-anchor, you could just do
3 <xsl:variable name="anchor-node"
select="$external-doc//my-anchor[(_at_)name = $anchor]" />
which is more or less as above.
<xsl:variable name="anchor-node" select="$external-doc//node()[name()
= 'my-anchor' and @name = @anchor]" />
or
<xsl:variable name="anchor-node" select="$external-doc//my-anchor[(_at_)name
= @anchor]" />
is also legal but tests the anchor attribute of the my-anchor element in
$external-doc is equal to the name attribute on the smae element.
David
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