Hi,
<xsl:key name="dkey" match="value" use="v1"/>
<xsl:for-each select="$ZZZ[generate-id(.)]/B[generate-id(.) =
generate-id(key('dkey',v1)[1])]">
[generate-id(.)] will always return true, so we can rewrite the above into
$ZZZ/B[generate-id(.) = generate-id(key('dkey',v1)[1])]
but this returns nothing, that is this does not return a nodeset...
i have a problem with the grouping.
any ideas?
How about
<xsl:for-each select="$ZZZ/B[generate-id(value) = generate-id(key('dkey',
value/v1))]">
<xsl:variable name="miktar" select="sum(key('dkey', value/v1)/v2)"/>
<fo:table-row>
<fo:table-cell>
<fo:block text-align="left" font-size="8pt" >
<xsl:value-of select='format-number($miktar, "###,###.00")'/>
</fo:block>
</fo:table-cell>
</fo:table-row>
</xsl:for-each>
Cheers,
Jarno
regards..
-----Original Message-----
From: Osman Çınar Eren
[mailto:Cinar(_dot_)Eren(_at_)isbank(_dot_)com(_dot_)tr]
Sent: Thursday, November 18, 2004 10:43 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [Bu posta banka dışından gelmekte olup gerektiğinde teyit
alınmalıdır.] - [xsl] find the sum over distinct nodes - Sender
blacklisted
Hi,
I have such an XML nodeset:
<A>
<B>
<key>aa</key>
<value>
<v1>aa</v1>
<v2>110</v2>
</value>
</B>
<B>
<key>bb</key>
<value>
<v1>bb</v1>
<v2>10</v2>
</value>
</B>
<B>
<key>cc</key>
<value>
<v1>cc</v1>
<v2>60</v2>
</value>
</B>
</A>
<A>
<B>
<key>bb</key>
<value>
<v1>bb</v1>
<v2>40</v2>
</value>
</B>
<B>
<key>cc</key>
<value>
<v1>cc</v1>
<v2>200</v2>
</value>
</B>
</A>
<A>
<B>
<key>dd</key>
<value>
<v1>dd</v1>
<v2>60</v2>
</value>
</B>
</A>
what i try to do is to have the sum values over 'v2' values
for distinct B nodes.(distinct means for different key values.)
i would like to have such an XSL part:
<xsl:for-each select="$ZZZ[generate-id(.)]/???">
<xsl:variable name="miktar" select="sum(v2)"/>
<fo:table-row>
<fo:table-cell>
<fo:block text-align="left" font-size="8pt" >
<xsl:value-of select='format-number($miktar,
"###,###.00")'/>
</fo:block>
</fo:table-cell>
</fo:table-row>
where $ZZZ is the nodeset which contrains the elements given above.
thanks in advance.
best regards..
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