Hi Kevin,
Have you declared your second variable "filename", too?
<xslvariable name="filename"/>
Wbr,
Roman
-----Ursprüngliche Nachricht-----
Von: Kevin Bird
[mailto:kevin(_dot_)bird(_at_)matrixdigitaldata(_dot_)co(_dot_)uk]
Gesendet: Dienstag, 9. November 2004 12:55
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Betreff: [xsl] Variables and command line params
Hi
I want to pass a second filename as a parameter from the command line.
The below variable declaration works in my stylesheet when the filename
is hardcoded.
<xsl:variable name="list2" select="doc('filename.xml')//supp"/>
But when I change to...
<xsl:variable name="list2" select="doc($filename)//supp"/>
...and add
filename="filename.xml"
to the command line option, I get an error - $filename has not been
declared.
Can someone please point out what I am doing wrong.
Thanks.
--
Kevin
--+------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail:
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--+--
**********************************************************************
This email and any files transmitted with it are confidential and
intended solely for the use of the individual or entity to whom they
are addressed. If you have received this email in error please notify
the system manager.
This footnote also confirms that this email message has been swept by
MIMEsweeper for the presence of computer viruses.
www.mimesweeper.com
**********************************************************************