--
Bryan Rasmussen
what I wrote earlier should solve that particular problem, text nodes have a
default template which is like this
<xsl:template match="text()">
<xsl:value-of select="."/>
</xsl:template>
this is why you don't actually have to use xsl:value-of to copy text, just
applying templates will copy without doing anything else unless you've
overridden the default template.
example overriding
<xsl:template match="text()"><xsl:text>I'm overriding the default text template
woo-hoo!</xsl:text>
<xsl:value-of select="."/>
</xsl:template>
Quoting "Bradley, Peter" <PBradley(_at_)uwic(_dot_)ac(_dot_)uk>:
Yeah. This neatly sums up the problems I've been having. An XPath
expression always seems to return an entire sub-tree, and it seems to me that
I just want a single node in this case. Will xsl-copy give me that?
Peter
-----Original Message-----
From: Geert Josten [mailto:Geert(_dot_)Josten(_at_)daidalos(_dot_)nl]
Sent: 08 November 2004 14:42
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Conditional extraction of data
M. David Peterson wrote:
ooops!
This portion:
<xsl:value-of select="foo"/> will output: "this is the value of foo"
<xsl:value-of select="foo"/> will output a copy of all the text elements
as well as the elements and there values that are descendants of foo. o
should have read...
<xsl:value-of select="foo"/> will output: "this is the value of foo"
Not true. xsl:value-of takes the first element from the node-set that results
from the expression
"foo" and converts that to a string. As both sub elements <bar> and <p> are
_inside_ element <foo>,
their textual content is returned as well.
The output is therefore: "
this is the value of foo
this is the value of bar.this is the value of a paragraph that is the
child of bar
"
(including new-lines when white-space is preserved)
<xsl:copy-of select="foo"/> will output a copy of all the text elements
as well as the elements and there values that are descendants of foo.
Sorry for the confusion!
<M:D/>
Grtz,
Geert
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